Show C code for opening text.txt using the open() linux syscall.

Show C code for opening text.txt using the open() linux syscall.

Certainly! Here's an example of C code that demonstrates how to open a file using the open() syscall in Linux:

 
#include <fcntl.h>
#include <stdio.h>
#include <unistd.h>
 
int main()
{
   // File path
   const char* file_path = "text.txt";
   
   // Open the file using the open() syscall
   int file_descriptor = open(file_path, O_RDONLY);
 
      if (file_descriptor == -1)
      {
         perror("Error opening the file"); return 1;
     }
 
   // File successfully opened, perform operations on it printf("File opened    successfully.\n");
   // Close the file using the close() syscall close(file_descriptor);
   return 0;
}

In this code snippet, the open() syscall is used to open the file "text.txt" with the O_RDONLY flag, which indicates that the file should be opened in read-only mode. The syscall returns a file descriptor, which is stored in the file_descriptor variable. If the open() syscall fails, it returns -1, and an error message is printed using perror(). Otherwise, a success message is printed, and the file is closed using the close() syscall.

Please note that this code assumes the file "text.txt" exists in the current directory. You may need to adjust the file path accordingly to match your specific scenario.

 

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